Sun System Handbook - ISO 3.4 June 2011 Internal/Partner Edition | |||
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Solution Type Technical Instruction Sure Solution 1007551.1 : Sun Fire[TM] V1280 Server, Sun Fire [TM] E2900 Server and Netra[TM] 1280 Server: Determining DIMM size and Location
PreviouslyPublishedAs 210450 Description This document provides you with information about determining DIMM sizes and physical locations on the Sun Fire[TM] V1280 Server, Sun Fire [TM] E2900 Server and Netra[TM] 1280 server. The DIMM sizes can be calculated from the Solaris[TM] Operating System and the System Controller. Steps to Follow FROM THE SYSTEM CONTROLLER Run the inventory command from the System Controller (SC), which gives you the part number of the DIMMs as well as the DIMM size. lom>inventory . . . (abridged) . . . /N0/SB0/P0/B0/D0: DIMM: 501-5401-03-50 serial# 3463A3 "256 MB NG SDRAM DIMM" Made on Sat Jun 01 21:23:22 GMT 2002 by 00c1 at IFR USA Signature = 00000000259f7e82 Powered on for 235 days 10 hours 26 minutes /N0/SB0/P0/B0/D1: DIMM: 501-5401-03-50 serial# 34659F "256 MB NG SDRAM DIMM" Made on Sat Jun 01 21:04:57 GMT 2002 by 00c1 at IFR USA Signature = 00000000259f7e82 Powered on for 235 days 10 hours 26 minutes . . In the preceding example the DIMMs are 256 MB and have the part number of 501-5401. FROM THE SOLARIS[TM] OPERATING SYSTEM 1) Run the /usr/platform/sun4u/sbin/prtdiag command. 2) Scroll down to the "Memory Configuration" subsection. . . (abridged) . . ==================Memory Configuration================== Bank Table: ----------------------------------------------------------- Physical Location ID ControllerID GroupID Size Interleave Way ----------------------------------------------------------- 0 0 0 512MB 0 1 0 1 512MB 4 2 0 0 512MB 8 3 0 1 512MB 12 4 1 0 512MB 1 5 1 1 512MB 5 6 1 0 512MB 9 7 1 1 512MB 13 8 2 0 512MB 2 9 2 1 512MB 6 10 2 0 512MB 10 11 2 1 512MB 14 12 3 0 512MB 3 13 3 1 512MB 7 14 3 0 512MB 11 15 3 1 512MB 15 Memory Module Groups: -------------------------------------------------- ControllerID GroupID Labels -------------------------------------------------- 0 0 SB0/P0/B0/D0,SB0/P0/B0/D1,SB0/P0/B0/D2,SB0/P0/B0/D3 0 1 SB0/P0/B1/D0,SB0/P0/B1/D1,SB0/P0/B1/D2,SB0/P0/B1/D3 Memory Module Groups: -------------------------------------------------- ControllerID GroupID Labels -------------------------------------------------- 1 0 SB0/P1/B0/D0,SB0/P1/B0/D1,SB0/P1/B0/D2,SB0/P1/B0/D3 1 1 SB0/P1/B1/D0,SB0/P1/B1/D1,SB0/P1/B1/D2,SB0/P1/B1/D3 Memory Module Groups: -------------------------------------------------- ControllerID GroupID Labels -------------------------------------------------- 2 0 SB0/P2/B0/D0,SB0/P2/B0/D1,SB0/P2/B0/D2,SB0/P2/B0/D3 2 1 SB0/P2/B1/D0,SB0/P2/B1/D1,SB0/P2/B1/D2,SB0/P2/B1/D3 Memory Module Groups: -------------------------------------------------- ControllerID GroupID Labels -------------------------------------------------- 3 0 SB0/P3/B0/D0,SB0/P3/B0/D1,SB0/P3/B0/D2,SB0/P3/B0/D3 3 1 SB0/P3/B1/D0,SB0/P3/B1/D1,SB0/P3/B1/D2,SB0/P3/B1/D3 Each Proccessor controls two physical banks of four DIMMs each. To improve interleaving, each physical bank is split into two logical banks by splitting each DIMM into two. Each logical bank is made up of one-half of each of four DIMMs in one physical bank. Therefore, each processor controls four logical banks, which are entries in the prtdiag table. Each entry in the prtdiag table represents 4 x 1/2 DIMMs. Therefore, if you half the size that appears in the logical bank, you arrive at the individual DIMM size. In the preceding example, each DIMM is 256 MB in size. The following diagram illustrates physical and logical bank relationships PHYSICAL BANK 0 PHYSICAL BANK 1 DIMM 0 ------------------------------- | half 0 - logical bank 0 | DIMM 0 ------------------------------- ------------------------------- | half 1 - logical bank 2 | | half 0 - logical bank 1 | ------------------------------- ------------------------------- | half 1 - logical bank 3 | DIMM 1 ------------------------------- ------------------------------- | half 0 - logical bank 0 | DIMM 1 ------------------------------- ------------------------------- | half 1 - logical bank 2 | | half 0 - logical bank 1 | ------------------------------- ------------------------------- | half 1 - logical bank 3 | DIMM 2 ------------------------------- ------------------------------- | half 0 - logical bank 0 | DIMM 2 ------------------------------- ------------------------------- | half 1 - logical bank 2 | | half 0 - logical bank 1 | ------------------------------- ------------------------------- | half 1 - logical bank 3 | DIMM 3 -------------------------------- ------------------------------- | half 0 - logical bank 0 | DIMM 3 ------------------------------- ------------------------------- | half 1 - logical bank 2 | | half 0 - logical bank 1 | ------------------------------- ------------------------------- | half 1 - logical bank 3 | ------------------------------- Also, using the attached diagram for the Sun Fire V1280 system board and the "Memory Module Groups" part of the "Memory Configuration" subsection of the prtdiag command output, you can determine which memory groups are currently populated. The prtdiag labels, for example SB0/P0/B0/D0, make the job easy. However, the order of the processors (P0, P1, P2, and P3) is different from their actual order on the system board. Their actual order on the board is from the inside out: P1, P0, P3, and P2. Product Sun Fire V1280 Server Netra 1280 Server Sun Fire E2900 Server Netra 1280, Sun Fire V1280, 1280, 2900, DIMM size, memory bank, logical bank Previously Published As 70174 Change History Audited/updated 11/24/09 - roberto.morandi@Sun.COM, Mid-Range Server Content Team Date: 2006-02-01 User Name: 25440 Action: Approved Comment: Publishing. Version: 11 Date: 2006-02-01 User Name: 25440 Action: Accept Comment: Version: 0 Date: 2006-02-01 User Name: 102144 Action: Approved Comment: Doc is accurate sent to Final review for publish. Version: 0 Date: 2006-02-01 Attachments This solution has no attachment |
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